6m^2+3m-4=0

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Solution for 6m^2+3m-4=0 equation:



6m^2+3m-4=0
a = 6; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·6·(-4)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{105}}{2*6}=\frac{-3-\sqrt{105}}{12} $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{105}}{2*6}=\frac{-3+\sqrt{105}}{12} $

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